$\int_0^{10}10e^{-10}dx$
$\int\left(\frac{x^2-25}{x-5}\right)dx$
$\:\left[\:\left(-5\right)^3\right]\:^4$
$2+6\:x\:5$
$49.2-8.03$
$\left(3^2\right)^2\cdot3^2$
$\left(\frac{3a^9}{b^9c^6}\right)^5$
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