$b^3b^4$
$\int_0^{\frac{\pi}{4}}\left(2sec^4\left(x\right)tan^4\left(x\right)\right)dx$
$\left(2r+6y\right)$
$\left(6p^2q+10p^3q^2\right)\left(6p^2q-10p^3q^2\right)$
$\frac{\cos^2x}{1-\sin x}$
$4x^2-12x+2$
$-875.38-80.08$
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