$\left(x^3-64\right)\left(x-4\right)$
$x^2-10x+90$
$\int_5^5\left(\frac{1}{8}\right)dx$
$\frac{\sec^2x\:\tan^2x\:-\:\tan^4x}{csc\:\left(-x\right)}$
$32-5\cdot2$
$\left(3x-7\right)\left(x\right)$
$12^2+20^2$
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