$\left(-\frac{1}{3}a+\frac{1}{4}b\right)^2$
$\lim_{x\to\infty}\:\left(ln\left(\frac{x+1}{x-6}\right)\right)$
$3x+12x^2-18x^3$
$\frac{1}{2}.\sin\left(\frac{\pi}{2}\right)$
$36a\:^6b\:^4-\:81c^2$
$\int\frac{6-7x}{x\left(x+2\right)}dx$
$-2^2\:-\:3-2\:+1$
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