$\int\frac{5x+3}{x^2+4}+\frac{4}{x}+\frac{6}{x^2}dx$
$\left(x-12\right)\left(x-4\right)$
$5-5x^3$
$\lim_{x\to\infty}\left(\frac{3^{lnx}-1}{lnx}\right)$
$\sqrt{44.8}$
$\frac{dy}{dx}=\left(\frac{2y\:+\:7}{8x\:+\:9}\right)^2$
$\left(2x^2\:+\:4x\:-\:3\right)\:\left(x^2\:-\:7x\:+\:1\right)$
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