$\frac{d}{dx}x^3+y^3=9xy$
$\frac{3a^3b+6a^2b^2-9ab^3}{3a^3b^3}$
$400p^{2}+40pz^{2}+1z^{4}$
$z^2-5z+9$
$-10+12+-15+10+18+-12+-18$
$0.4\left(x+5\right)=0.3\left(4x+2\right)$
$x^2-16x-36$
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