$\frac{10}{x+8}=\frac{5}{x\left(x+1\right)}$
$64x^2-49y^2$
$4x+10\le-2x-8$
$5x-10<2x-10$
$\int-\frac{2}{x^{\frac{1}{4}}}dx$
$25x^2+20\:xz+4z^2$
$\frac{9x}{2}+\frac{9x}{2}+\frac{9x}{2}+\frac{9x}{2}$
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