$\left(4+4\right)^2-10$
$\:2xy\:dx\:+\:\left(y^2\:-\:3x^2\right)\:dy\:=\:0$
$\int x^2\left(x^3-3\right)^8dx$
$-4-6p+8p-8+6p$
$\int\left(5x+3\right)^7dx$
$\int-8cos\left(5y+4\right)dy$
$\sqrt[3]{2^3}$
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