$x^2+16x=5$
$\frac{\left(6zw^4\right)}{\left(8z^2w^6\right)}$
$5^y=125$
$\int5ay^2dy$
$\lim\:_{x\to\:\infty\:}\left(\sqrt{4x^2-x+6}-2x+\frac{5}{4}\right)$
$9\:x^2-1\:=\:0$
$\lim_{x\to\infty}4xe^{-9x}$
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