$\left(x^2+x-2\right)\left(x^2+3x\right)$
$\lim_{x\to0}\left(\frac{\left(1+x\right)^6-\left(1+6x\right)}{x^2+7x}\right)$
$\frac{\tan18}{\tan54-\tan36}$
$13-7\left(5\cdot4\right)$
$9x^2+60x+100=0$
$\lim_{x\to\infty}\left(xe^{-2\sqrt{x}}\right)$
$\sqrt{324}$
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