$y'=\left(\frac{\left(2y+3\right)}{4x+5}\right)^2$
$10x-5+9-3x$
$\left[-4-\left(-5\right)+5\right]-1$
$3x^2+7x+4$
$\frac{4x^2}{5y}^3$
$\sec\left(x+1\right)\left(\sec-1\right)$
$\frac{dy}{dx}=-e^y\sin\left(x\right)$
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