$6x\:+\:3\ge x\:-\:9$

$\int\frac{\left(x+1\right)}{\left(x^2+4x+5\right)}dx$

$\left(\frac{2}{5}xy-\frac{3}{4}x^2n+1\right)^2$

$\lim_{x\to9}\left(\frac{\left(x-9\right)}{\left(\sqrt[2]{x}\:-3\right)}\right)$

$\lim\:_{x\to\:-3}\left(\frac{\left(6x\right)^2+6x-36}{x+3}\right)$

$\cot^2\:\left(x\right)\cdot\left[1+\tan^2\left(x\right)\right]=\csc^2\left(x\right)$

$-x^2=-3x-18$