$20a^3+25+4a^6$
$\left(3u^7v^3\right)\left(4u^4v^{-5}\right)$
$\frac{1}{5}-\frac{2}{3}x\:+\:\frac{3}{4}x+2y\:-\:\frac{3}{7}-4x+3y$
$-\sqrt{3}+\sqrt{3}-5\cdot\sqrt{3}$
$\left(7^2\right)^x=\left(7^3\right)^g$
$e^x\:\frac{dy}{dx}\:=\:2x$
$\left(-a^3-4a^2+5\right)-\left(a^3-2a^2+6\right)$
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