$5\cdot5\cdot\left(-10\right)$
$-12\le\left|-3\right|$
$\frac{6}{\infty}$
$x+2\cdot4$
$\left|3-\left(7\cdot8\right)\right|-8$
$16-\left(-10\right)$
$\frac{\left(x+3\right)+\left(x-1\right)}{\left(-x+1\right)}$
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