$6x+2y=5x-4y+8$
$\frac{d}{dx}2x^2+2y^2=1$
$\log\left(a\right)+2\log\left(b\right)-3\log\left(c\right)$
$\frac{x^4-x}{3x^2}$
$2u-5=5$
$\:\:_{\left(-4\right)}^3+\:7\left(-4\right)^2+\:5\left(-4\right)\:-28$
$\left(9a-c\right)^2$
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