$\frac{d}{dx}\tan^34x=\left(\tan\left(4x\right)\right)^3$
$7z=-21$
$x y ^ { \frac { 1 } { 2 } } = 1$
$\cos^2x-3\sin\left(x\right)=0$
$\frac{m+3}{m-3}+\frac{m+2}{m-2}$
$-3.2^2-5.2+4$
$\int\frac{4}{x^2-10x+26}dx$
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