$cos\left(3x\right)=-\frac{\sqrt{3}}{2}$
$\left(16x^2-y\right)^2$
$y=\frac{\sqrt{x^2-25}}{x^2+4x-12}$
$\left(-8w\right)\cdot\left(\frac{1}{56}w\right)$
$x-y=8$
$x\cdot x$
$\sqrt{25x^4y^5}$
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