$\left(3h^6-4\right)^2$
$\lim_{x\to\infty}\left(\frac{\cos\left(x\pi\right)}{x}\right)$
$3\cdot\left(-2\right)\cdot3$
$-4x<18$
$d^2-4ad+4a^2$
$\lim_{x\to0}6x^2-x+3$
$\frac{b-2}{b-8}\:=\:\frac{b+3}{b}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!