$\lim_{n\to\infty\:}\left(0\right)^{n+1}-1$
$\frac{1}{6}.\int\frac{1}{x+1}dx$
$\frac{8x^3}{2x^9}$
$\lim_{z\to\infty}\left(\frac{z^2+1}{z-1}\right)$
$\left(9-16m\right)\left(9+16m\right)$
$7d-8d$
$\lim_{x\to\infty}\left(\frac{4+4x-2x^2}{e^x}\right)$
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