$1-\frac{x}{5}\leq0$

$\lim_{x\to1}\left(\frac{x-1}{x+1}\right)$

$\int\left(\frac{\left(1+e^2\right)}{\left(1-e^2\right)}\right)dx$

$11^2\cdot11\left(-4\right)$

$\lim_{x\to\infty}x^{ln\left(\frac{\left(x+1\right)}{x}\right)}$

$16x^2+4y^2$

$\lim_{x\to0}\left(\frac{1-6x}{x}\right)$