$20x+4+28x^2$
$19\:\:-\:\:\left(-15\right)\:\:$
$3x^2-5x+2=-1$
$\lim_{x\to0}\left(\frac{1}{\ln\left(1+x\right)}-\left(\frac{1}{\tan\left(2x\right)^{-1}}\right)\right)$
$\frac{7+8\:cos\left(y\right)}{8+7\:sec\left(y\right)}$
$\left(3a\:-\:7b\:+\:5c\right)-\left(4b\:+\:2c\right)$
$5x-7+8y-3x+5y+2$
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