$-\frac{3y}{8}-4\le32$
$\lim_{x\to\infty}\left(\frac{e^{2x}}{x^2+1}\right)$
$2x^2+3x+20$
$-6+7x-4x-20$
$3xy^2\left(x^3+2xy-8y^3\right)$
$\left(6x+2y\right)^4$
$\frac{d}{dx}\left(\frac{5xy}{1+y^2}=\arctan\left(y\right)\right)$
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