$-y^2+2y+16$
$\int\left(\left(2x+4\right)\cdot\cos\left(x^2+4x\right)\right)dx$
$\left(3.5xy+2.5x\right)^2$
$4\sin x-3=0$
$\left(3x^{\frac{3}{4}}y^{\frac{3}{4}}\right)^3$
$\int_1^2\left(\frac{x}{\left(x^2-1\right)^2}\right)dx$
$\frac{12a^4}{3\left(a^5\right)^3}$
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