$4^x-3\left(2^x\right)-4=0$
$\left(9a^4+5b^3\right)^2$
$13=v-7$
$2x\frac{1}{2}-\left(2y\right)\frac{1}{2}$
$\frac{1}{1-cos\left(x\right)}=8$
$-44\left(-1\right)$
$\left(-24x^2+120x-150\right)\cdot\left(\frac{1}{4}x^2-\frac{5}{4}x+\frac{25}{16}\right)$
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