$-3x\left(x+7\right)+\left(2x-1\right)\left(-3x+2\right)$
$3\left(x-6\right)-8\left(x-4\right)>2\left(7x-7\right)$
$\frac{5ca^6}{3b^6c^{-1}}$
$\frac{6}{x^2-2x-8}$
$2.34\cdot1.3$
$\log\left(x\right)+\log\left(x+5\right)=\log\left(6x+12\right)$
$\left(4x^2y-3z^2q^3\right)^3$
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