$0^2+2\cdot0\cdot3+3^2$

$\frac{4}{x+4}+\frac{6}{2x+3}=\frac{-6}{2x^2+11x+12}$

$\frac{dy}{dx\:}=\frac{x^3}{y^2}$

$xy^2+2y-xy=0$

$\lim_{x\to\infty}\left(\frac{\sqrt{x^5+1}}{x^3+1}\right)$

$\int\left(3x-2\right)e^{-\frac{3}{2}x}dx$

$\frac{\left(3x-6\right)^n}{2^n\sqrt{n+1}}$