$54a^3+108a^2b+72ab^2+16b^3$

$\frac{d}{dx}\left(4y-8x^3=20\right)$

$\frac{2a-3}{a-3}-2=\frac{12}{a+3}$

$\frac{d}{dx}\:y=x^4tgx$

$4-\left|-3\right|\cdot5\cdot\left|-2\right|-5-4\cdot\left|-6\right|\cdot3$

$\left(-2\right).12+\left(-2\right).\left(-6\right)$

$\left(6x^2y\right)\left(4x^3y^4\right)$