$\left(482.694\right).\:\left(29\right)$
$\left(2a^3-4a\right)^3$
$\left(x^2+4xy^3\right)^3$
$\frac{dy}{dx}=\frac{7x}{4y}$
$\frac{d^2}{dx^2}\left(3sen\left(x^2-1\right)\right)$
$-8\cdot11+9$
$\left(\text{4xy + 5y^2}\right)^2$
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