$\left(n^3+7\right)\left(x^3-6\right)$
$\frac{x^3-x^2+8x-8}{x+1}$
$\int9t^3cos\left(t^2\right)dx$
$\frac{6t-15}{3t-2}$
$\left(6\sqrt{16}\right)\cdot\left(3\sqrt{8}\right)$
$\frac{dy}{dx}=\frac{y\left(x^2-1\right)}{y+1}$
$5x-8=x+4$
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