$\left(-33\right)+\left(12\right)+\left(-2\right)+\left(1\right)$
$\frac{9yx^2}{3xy}$
$2b+3c+4b-\left(-1\right)$
$1a^{10}-2a^5$
$\frac{\left(2-a\right)\left(a+4\right)}{a-3}$
$\left(\frac{3x}{x-3}\right)+\left(2\right)=\left(\frac{3x-1}{x+3}\right)$
$x-3\le-3$
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