$\frac{7}{\frac{1}{6}}$
$0.25a+0.5=4.5$
$-6z=12$
$\frac{20}{6-3x}\le2$
$8v^3\cdot4vu^2$
$y=x^{-\frac{1}{7}}$
$\left(+7\right)\cdot\left(-13\right)\cdot\left(+3\right)\cdot\left(-8\right)$
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