$\frac{m^2}{m}-\frac{25}{5}$
$\frac{2\sec\left(x\right)}{\tan\left(^2\right)x}$
$\tan\left(x\right)\cdot\left(\tan\left(x\right)-2\right)=6$
$a^2+4a-21=0$
$\left(-3a^2-4a+2\right)-\left(5a^3+2a-6\right)$
$2\ln\left(x\right)=14$
$1+9+4x^2$
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