$\left(3x\:-\:1\right)\left(a\:+\:3b\right)\:$
$\left(x+3x\right)+\left(x-3x\right)$
$\frac{dy}{dx}\left(\frac{3x^4-9x^3+5}{x^2}\right)$
$\left(4y-9z\right)^3$
$\int x^{-4}\:dx$
$4-12\cdot\left(-2\right)$
$-7x-3y+3z=12$
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