$\int x^3\left(1+t^4\right)^3dx$
$-7x=28$
$\lim_{x\to5}\left(\frac{12x-60}{x^2+6x+5}\right)$
$3a\left(4a-5b\right)\:$
$\left(\frac{\sin^2x}{\sec^2x-1}\right)=\cos^2x$
$\:\frac{cos^2b-7sin^2b}{1-8sin^2b}$
$-3a+52a$
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