$\int\frac{1}{\left(e^{2x}+4e^x\right)}dx$

$\:f\left(x\right)\:=\:\:3x\:-\:4\:y\:g\left(x\right)\:=\:12\left(x+4\right)$

$\left(7n^2+6\right)\left(3n^2-0.8\right)$

$496\cdot2$

$\int_{-0.5}^2\left(3x^2+1\right)dx$

$4x^2-6x-9$

$\int_{z^2}^{8-z^2}\left(2\sqrt{4-z^2}\right)dz$