$x^2+5x-13=0$
$2x+1\:para\:x=0$
$\lim_{x\to1}\left(\frac{3\cos\left(1-x\right)}{\left(x\right)\ln\left(1+3\ln\left(x\right)\right)}\right)$
$\frac{20x^5+3x-2x^3-10}{x+1}$
$4t^{-\frac{3}{8}}$
$\left(-9x^2y^2\right)\left(8xy^4\right)$
$5x+24=2x+9$
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