$\int\left(\sin^3\left(3x\right)\cdot\cos\left(3x\right)\right)dx$
$-2x^2-6x+36$
$\left(\frac{1}{xy}\right)\left(\frac{1}{x}\right)+\frac{1}{y}$
$g2+26g+169$
$x^2+10x+56$
$4x^4-30x^3y+25x^2y^2$
$\frac{dy}{dx}=5x+y+2,y\left(0\right)=4$
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