$\left(18x^4\:-\:3y\right)^2$
$\int\frac{-1}{4}\left(x-7\right)dx$
$\frac{2}{1-x^7}$
$\sec\left(240^{\circ}\right)$
$xy-y=2x^2y$
$6x-\left(5x-7\right)$
$\sqrt{6a^2}\cdot\sqrt{3a^4}$
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