$5c\:+\:4+c\:+2$

$\int\frac{\left(x-1\right)^2\left(x+1\right)}{\left(x^2+1\right)^3}dx$

$\int\frac{1}{2x-3}dx$

$\lim_{x\to2}\left(\frac{x^2-3x+2}{x^2-4x+4}\right)$

$\tan\left(3\right).\tan\left(3\right)\cdot\cos\left(3\right).\cos\left(3\right).\cot\left(3\right)\cdot\cot\left(3\right)\cdot\sin\left(3\right).\sin\left(3\right)=1$

$\frac{1}{6}x^2+\frac{1}{3}x<4$

$3+9x-4$