$ax+bx+cx$
$\frac{d^3}{dx^3}\:x^3$
$ydx-xdy=xdy-xydx$
$\frac{dy}{dx}\left(x+y-y^2=15\right)$
$\:sinh\left(x+y\right)=sinh\left(x\right)cosh\left(y\right)+cosh\left(x\right)sinh\left(y\right)$
$\frac{dy}{dx}+y^2=y$
$\left(anp^2+6qr^3\right)^2$
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