$\frac{d}{dx}\left(2x+1\right)^5\left(x^3-x+1\right)$
$\int\frac{x^2-x-3}{\left(x+4\right)\left(x-2\right)}dx$
$\frac{1}{\csc\left(9\right)}$
$\left(y^2+7\right)^2$
$c^2-5c=0$
$9+\frac{n}{2}>16$
$\left(\frac{5}{4}x\right)\left(-\frac{1}{3}\right)$
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