$\left(\frac{3}{4}x^2y^3\right)\left(\frac{2}{3}xy\right)\left(\frac{5}{4}x^2y^3\right)$

$\frac{dy}{dx}=\left(x+y\right)\frac{1}{-x}$

$\left(6-2\right)\cdot10$

$\left(5x^4-xy\right)\left(5x^4-5yx\right)$

$2x^2\left(x^4+2y\right)$

$-5\left(1+\left(-7\right)\right)$

$14^{-5}\cdot14^5$