$9-3x=-18$
$\frac{2t^3-6t^2-20t}{12^3+18t^2-12t}$
$12.\:\left(-9\right)\:.\:\left(-12\right)$
$2\left(x+3\right)-3\left(x-4\right)<\:x+8$
$y'-4y=0$
$\cos\left(x+\pi\right)=\cos\left(x\right)$
$\int\frac{6}{3^{5x}}dx$
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