$3\cos^2+2\sin^2=3$
$\left(1+\frac{1}{4}x\right)^{-\frac{1}{2}}$
$\int\left(6x^2+4\right)^3dx$
$m+n-d-m-n+d$
$0=ydx+dx-xdy$
$\sqrt{16x^4}$
$\int\frac{\left(\cos\left(12\right)\right)}{\left(\sin\left(12\right)\right)}dx$
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