$-3\:\left(-2\right)\left(1\right)$
$\int\frac{\left(x^2+6\right)}{x^3+3x}dx$
$\frac{8a^9+27b^6}{2a^3-3b^2}$
$x^2-2x=35$
$232.22-122.4$
$\frac{dy}{dx}=x^2+5x+2$
$\frac{\left(x^3-x^2-x\right)}{\left(x-1\right)}$
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