$6ab^2\:+3b$
$\int\frac{5}{x^2-2x-3}dx$
$a+2a+9a$
$\frac{dy}{dx}=\frac{1}{2}x^2\left(1+y^2\right)$
$-8\:\cdot\:9\:+\:-8\:\cdot\:7$
$\left(2x-3\right)-\left(x+2\right)^2-3\left(x-6\right)$
$\frac{d}{dx}arc\:cos\:x^2$
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