$144\:a\:^2\:\:100\:b^2$
$\int\frac{z^3}{\sqrt[3]{4+z^4}}dz$
$\lim\:_{x\to\:3}\:\left(\frac{x-50}{x^2-6x+9}\right)$
$1.44\left(x^2+1\right)-0.09$
$\frac{64x^3y}{2^3xy}$
$5x^2+340x-1428$
$x^4+x^3-30x^2$
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