$\left(8x^3y^4z\right)^2$
$9\left(3x-7\right)$
$\frac{d^3}{dx^3}\left(2\cdot\sin\left(x\right)\right)$
$\tan\left(\frac{1}{2}\right)x+1=0$
$\left(95\right)-\left(-23\right)$
$9\left(a\:+\:1\right)\left(a\:+\:2\right)\:-\:9$
$14a^3b^4-7a^2b^2+28a^8b^8$
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