$\left(2d-3\right)\left(2d+3\right)$
$12x=36$
$-9z+-63$
$3x\:+\:2y\:+\:10\:+\:3y\:-\:2x\:-\:7$
$\int\frac{2}{\sqrt{x^2-2x-8}}dx$
$6y+8$
$\frac{dy}{dx}=\frac{1}{y^2}\:$
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