$4-10.4\:x\:4^6$
$\int40xe^{-8x}dx$
$3x^3+x^2-2x-y=-1$
$\ln ax$
$-2w^3\left(-4w^6\right)$
$b^2-12+36$
$4x\left(3x+1\right)-3\left(3x+1\right)$
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